Prove that : cos20°/sin70° + cosθ/sin(90° - θ) = 2 - Sarthaks

Prove that : cos20°/sin70° + cosθ/sin(90° - θ) = 2

SOLVED: Express the given product as a sum containing only sines

The value of sin 50°– sin 70° + sin 10° is equal to A. 1 B. 0 C. 1

Prove that (cos 20°−𝑠𝑖𝑛20°)/(cos 20°+𝑠𝑖𝑛20°)=tan⁡25°

cos 20^(@)),(sin 70^(@), cos 70^(@))

Find the value off the following: (cos^2 20° + cos^2 70°)/(sin^2

सिद्ध कीजिए कि(cos theta)/(sin(90^(@)-theta))+(sin

Simplify the following: Cos20°/Sin70° + CosA/Sin(90°-A)

Prove that: Sin 70/cos 20 cosec20/sec 70 -2cos 70 cosec 20 = 0

सिद्ध कीजिए कि (sin ^(2)20^(@)+sin^(2)70^(@))/(sin

How to prove sin 70°/cos 20° = 1 without using a trigonometry

सिद्ध कीजिए कि(cos theta)/(sin(90 deg - theta)) + (sin theta)/(cos(90 deg - theta)) = 2

Prove thal T-cos e + 1+cos =2 OR cos 55'. cosec 35 tan 5. tan 25