A solution is be kept between 40^(@)C and 45^(@)C. What is the range o

Let the required temperature be x^(@)F. Given that, F=9/5 C+32 rArr 5F = 9C+32 xx 5 rArr 9C=5F-32 xx 5 :. C=(5F-160)/9 Since, temperature in degree calcius lies between 40^(@)C to 45^(@)C. Therefore, 40 lt (5F-160)/9 lt 45 rArr 40 lt (5x-160)/9 lt 45 rArr 40 xx 9 lt 5x - 160 lt 45 xx 9 [ multiplying throughout by 9] rArr 360 lt 5x - 160 lt 405 [ adding 160 throughout] rArr 360 + 160 lt 5x lt 405 + 160 rArr 520 lt 5x lt 565 rArr (520)/5 lt x lt (565)/5 [ divide throughout by 5} rArr 104 lt x lt 113 Hence, the range of temperature in degree fahrenheit is 104^(@)F to 113^(@)F.

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A solution is to be kept between 40°C and 45°C. What is the range of temperature in degree Fahrenheit, if

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