Home negative i

The Complex Number i is NOT the square root of negative one! (TANTON Mathematics)

By A Mystery Man Writer

How do you find the square roots of a complex number?

Determining the Nth Roots of a Complex Number

Find the square root of the complex numbers: -i

How to Find the Square Root of a Negative Number

Matrices 12: Where do Complex Numbers come from?

The Complex Number i is NOT the square root of negative one

What is wrong with this paradox of complex number: [math]-1=i^2=i

$\begin{array}{ll}\left(\frac{1}{\sqrt{2}}+\frac{i}{\sqrt{2}}\right)^2\\[2mm]=\left(\frac{1}{\sqrt{2}}+\frac{i}{\sqrt{2}}\right)\left(\frac{1}{\sqrt{2}}+\frac{i}{\sqrt{2}}\right)\\[2mm]=\frac{1}{\sqrt{2}}\left(1+i\right)\frac{1}{\sqrt{2}}\left(1+i\right)\\[2mm]=\frac{1}{2}\left(1+i\right)\left(1+i\right)\\[2mm]=\frac{1}{2}\left(1+i+i+i^2\right)\\[2mm]=\frac{1}{2}\left(1+i+i-1\right)\\[2mm]=\frac{1}{2}\left(2i\right)\\=i\end{array}$

Q: “i” had to be made up to solve the square root of negative one. But doesn't something new need to be made up for the square root of i?

Proof of iota power iota, what is i^i

Modulus of negative numbers

Imaginary unit - Wikipedia

Square and Cube Root of a Negative Number BE CAREFUL

Eddie's Math and Calculator Blog: 2012

Reflections and Tangents, Thoughts on Math, Education, and Technology